Questions
A parallel plate capacitor made of circular plate each of radius 10 cm has a capacitance 200 pF. The capacitor is connected to a 200 V supply with an angular frequency of 200 rad/s. What is the peak value of displacement current?
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Correct option is B
RMS current , Irms=ErmsXc ⇒Irms=Erms1/wC ⇒Irms=wC×Erms ⇒Irms=200×2×10−10×200=8μAPeak value of displacement current is Io=2Irms=2×8×10−6A=82μASimilar Questions
A parallel plate capacitor of plate separation 2 mm is connected in an electric circuit having source voltage 400 V. if the plate area is 60 , then the value of displacement current for will be
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