A parallel plate of capacitor made of circular plates each of radius $20.0cm$ has a capacitance $100pF$. The capacitor is connected to a source of 220 V and angular frequency of  $200rad/s$, the rms value of the displacement current is __________$\mu A$ 

Given : $Erms=220V,\omega =200rad/s$

Capacitance,  $C=100pF=100\times {10}^{-12}F$
Rms value of the displacement current is same as  conduction current =  $Irms=\frac{Erms}{X_C}$
$$\begin{gathered} \Rightarrow Irms=\frac{Erms}{1/\omega C} \\ \Rightarrow Irms=Erms\times \omega C =220\times 200\times 100\times {10}^{-12}=44\times {10}^{-7}=4.4\times {10}^{-6} \end{gathered}$$     
$\Rightarrow Irms=4.4\mu A$