Download the app

Questions  

A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 x 104 V/m, the charge density of the positive plate will be close to: 

a
6×104C/m2
b
6×10−7C/m2
c
3×10−7C/m2
d
3×104C/m2

detailed solution

Correct option is B

E=σε=σKε0=3×104V/m ∴σ=Kε0×3×104       =2.2×8.854×10−12×3×104=6×10−1Cm−2

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
 


phone icon
whats app icon