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A parallel plate capacitor of plate separation 8.85 mm is connected in an electric circuit having source voltage 400V. What is the value of the displacement current for10-6  sec , if the plate area is 60cm2 ?

a
2.4mA
b
1mA
c
4.2mA
d
2.2mA

detailed solution

Correct option is A

Displacement current ID=∈odϕEdt   since  ID=dqdtand ϕ=q∈0                                          ⇒ID=∈oEAt ⇒ID=∈o(V/d)At ⇒ID=8.85×10−12×400×60×10−48.85×10−3×10−6 ⇒ID=24×10−4A=2.4×10−3A = 2.4 mA

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