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Q.

A parallel plate capacitor of plate separation 8.85 mm is connected in an electric circuit having source voltage 400V. What is the value of the displacement current for10-6  sec , if the plate area is 60cm2 ?

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a

2.4mA

b

1mA

c

4.2mA

d

2.2mA

answer is A.

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Detailed Solution

Displacement current ID=∈odϕEdt   since  ID=dqdtand ϕ=q∈0                                          ⇒ID=∈oEAt ⇒ID=∈o(V/d)At ⇒ID=8.85×10−12×400×60×10−48.85×10−3×10−6 ⇒ID=24×10−4A=2.4×10−3A = 2.4 mA
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