First slide

Maxwell's displacement current

Question

A parallel plate capacitor of plate separation 8.85 mm is connected in an electric circuit having source voltage 400V. What is the value of the displacement current for $10^{- 6}$ sec , if the plate area is $60 c m^{2}$ ?

Moderate

A

$2.4 m A$
B

$1 m A$
C

$4.2 m A$
D

$2.2 m A$

Solution

Displacement current $I_{D} = \in_{o} \frac{d ϕ_{E}}{d t}$ $\sin c e I_{D} = \frac{d q}{d t} a n d ϕ = \frac{q}{\in_{0}}$
$\Rightarrow I_{D} = \in_{o} \frac{E A}{t} \Rightarrow I_{D} = \in_{o} (V / d) \frac{A}{t} \Rightarrow I_{D} = \frac{8.85 \times 10^{- 12} \times 400 \times 60 \times 10^{- 4}}{8.85 \times 10^{- 3} \times 10^{- 6}} \Rightarrow I_{D} = 24 \times 10^{- 4} A = 2.4 \times 10^{- 3} A = 2.4 m A$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App