First slide

Capacitance

Question

A parallel plate capacitor with air between the plates has a capacitance of 9 pF. The separation between its plates is d. The space between the plates is now filled with two dielectrics. One of the dielectric has dielectric constant k₁ = 3 and thickness d/3 while the other one has dielectric constant k₂ = 6 and thickness 2d/3. Capacitance of the capacitor is now

Moderate

A

20.25 pF
B

1.8 pF
C

45 pF
D

40.5 pF

Solution

$C = \frac{ϵ_{0} A}{d} = 9 pF C_{1} = k_{1} \frac{ϵ_{0} A}{d / 3} = 3 k_{1} \frac{ϵ_{0} A}{d} = 3 \times 3 \times 9 = 81 pF C_{2} = k_{2} \frac{ϵ_{0} A}{2 d / 3} = 3 k_{2} \frac{ϵ_{0} A}{2 d} = 3 \times 6 \times \frac{9}{2} = 81 pF$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App