A parallel plate capacitor with air as dielectric is charged to a potential V. It is then connected to an uncharged parallel plate capacitor filled with wax of dielectric constant K. The common potential of both capacitor is
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a
V
b
KV
c
(1+K)V
d
V/(1+K)
answer is D.
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Detailed Solution
Before connection, the charge Q on the plates of air filled capacitor is C V. After it is connected with an uncharged capacitor, let y' be the common potential. Let Q1 and Q2 be the charges on charged and uncharged capacitor respectively. ThenQ1=V′C and Q2=V′(KC)∴ CV=V′C+V′(KC)=(1+K)V′C or V′=V1+K