A parallel plate capacitor with plate area ‘A’ and separation $$b/w$$ the plates ‘d’ is charged by a constant current ‘i’. Consider a plane surface of area $$A/2$$ parallel to the plates and drawn symmetrically between the plates. The displacement current through this area is

Question

A parallel plate capacitor with plate area ‘A’ and separation $$b/w$$ the plates ‘d’ is charged by a constant current ‘i’. Consider a plane surface of  area  $$A/2$$ parallel  to the plates and drawn symmetrically between the plates. The displacement current through this area is

Infinity Learn · Accepted Answer

$$ic=i=dqdt$$ Here $$ic=$$ conductional current    $$dqdt=$$ rate of flow of charge  ⇒$$id=$$∈$$0d$$ϕ$$dt=$$∈$$0ddtEA2$$                      $$E=qA$$∈$$0$$ ⇒$$id=$$∈$$0A2ddtqA$$∈$$0$$ ⇒$$id==$$∈$$0A2$$×$$1A$$∈$$0dqdt=12dqdt=i2$$

A parallel plate capacitor with plate area ‘A’ and separation b/w the plates ‘d’ is charged by a constant current ‘i’. Consider a plane surface of area $A / 2$ parallel to the plates and drawn symmetrically between the plates. The displacement current through this area is

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A parallel plate capacitor with plate area ‘A’ and separation b/w the plates ‘d’ is charged by a constant current ‘i’. Consider a plane surface of area A/2 parallel to the plates and drawn symmetrically between the plates. The displacement current through this area is

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A parallel plate capacitor with plate area ‘A’ and separation b/w the plates ‘d’ is charged by a constant current ‘i’. Consider a plane surface of area $A / 2$ parallel to the plates and drawn symmetrically between the plates. The displacement current through this area is