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Q.

A parallel plate capacitor with plate area ‘A’ and separation b/w the plates ‘d’ is charged by a constant current ‘i’. Consider a plane surface of  area  A/2 parallel  to the plates and drawn symmetrically between the plates. The displacement current through this area is

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a

i2

b

i3

c

i4

d

i8

answer is A.

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Detailed Solution

ic=i=dqdt Here ic= conductional current    dqdt= rate of flow of charge  ⇒id=∈0dϕdt=∈0ddtEA2                      E=qA∈0 ⇒id=∈0A2ddtqA∈0 ⇒id==∈0A2×1A∈0dqdt=12dqdt=i2
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A parallel plate capacitor with plate area ‘A’ and separation b/w the plates ‘d’ is charged by a constant current ‘i’. Consider a plane surface of  area  A/2 parallel  to the plates and drawn symmetrically between the plates. The displacement current through this area is