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Q.

A parallel plate capacitor with plate area A and separation between the plates d, is charged by a constant current i. Consider a plane surface of area A/2 parallel to the plates and drawn simultaneously between the plates. The displacement current through this area is

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a

i

b

i/2

c

i/4

d

i/8

answer is B.

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Detailed Solution

Charge on capacitor plates at time t is, q = it Electric field between the plates at this instant.E=qAε0=itAε0Electric flux through the given areaϕE=A2E=it2ε0Therefore, displacement currentid=ε0dϕEdt=ε0ddtit2ε0=i2

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