A parallel plate condenser of capacity C is connected to a battery and is charged to a potential V. Another condenser of capacity 2 C is connected to another battery and is charged to a potential 2 V. The charging batteries are removed and now the condensers are connected in parallel in such a way that the positive plate of one is connected to negative plate of other. The final energy of this system is
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a
zero
b
3CV2/2
c
5CV2/2
d
9CV2/2
answer is B.
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Detailed Solution
The common potential is given byV=C2V2−C1V1C1+C2=4CV−CV3C=VThe energy stored by the combination is given byU=12CV2=12(3C)V2or U=3CV22