Questions
A parallel plate condenser of capacity is connected to an AC supply Voltage . The maximum displacement current is
detailed solution
Correct option is C
Displacement current=conduction currente=e0sin(ωt) standard equatione=4sin(100πt) given equationOn comparing the above equations we get e0=4Volt & ω=100π rad/sNow, we know that,ID=e0XC where XC=1ωC ⇒ID=e01/ωC=e0×ωC ID=4×100π×10×10−6A ID=4π×10−3A=4πmATalk to our academic expert!
Similar Questions
A parallel plate capacitor of plate separation 2 mm is connected in an electric circuit having source voltage 400 V. if the plate area is 60 , then the value of displacement current for will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
