Q.

A parallel plate condenser of capacity 10μF is connected to an AC supply Voltage e=4sin(100πt) . The maximum displacement current is

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a

4πμA

b

2.8πμA

c

4πmA

d

2.8πmA

answer is C.

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Detailed Solution

Displacement current=conduction currente=e0sin(ωt) standard equatione=4sin(100πt) given equationOn comparing the above equations we get e0=4Volt  & ω=100π  rad/sNow, we know that,ID=e0XC   where XC=1ωC   ⇒ID=e01/ωC=e0×ωC ID=4×100π×10×10−6A ID=4π×10−3A=4πmA
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A parallel plate condenser of capacity 10μF is connected to an AC supply Voltage e=4sin(100πt) . The maximum displacement current is