A parallel plate condenser with a dielectric of dielectric constant K between the plates has a capacity C and is charged to a potential V volts. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is
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a
12(K−1)CV2
b
CV2(K−1)/K
c
(K−1)CV2
d
zero
answer is D.
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Detailed Solution
On introduction and removal and again on introduction, the capacity and potential remain same. So, net work done by the system in this process.W=Uf−Ui;12CV2−12CV2=0