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Total internal reflection - Ray optics and optical instruments

Question

A parallel sides slab ABCD of refractive index 2 is sandwiched between two slabs of refractive indices 2 and 3 as shown in the Fig. The minimum value of angle θ (in degrees) such that the ray PQ suffers total internal reflection at both the surfaces AB and CD is

Moderate
Solution

Refer to Fig.

For total internal reflection at surface AB, angle θ must be greater than or equal to the critical angle i1 given by

sini1=μ2μ1=22=12

which gives i1=45

For total internal reflection at surface CD, angle θ must be greater than or equal to the critical angle i2 given by

sini2=μ3μ1=32

which gives i2=60

Hence, for total internal reflection at both the surfaces AB and CD, the minimum value of θ = 60°. 



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