A parallel-plate air-spaced capacitor of capacitance C and a resistor of resistance R are in series with an ac source of frequency ω. The voltage-drop across R is VR. Half the capacitor is now filled with a material of dielectric constant K but the remainder of the circuit remains unchanged. The voltage-drop across R is now 2VR. Neglecting edge effects, the dielectric constant K is m1−nR2C2ω2−1. Find the value of m + n.
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answer is 7.
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Detailed Solution
When half the capacitor is filled with the material, the capacitance of the capacitor (two capacitors in parallel) becomes C′=C2+KC2The voltage across R is VZR, where V is the voltage of the ac source and Z is the total impedance of the circuit. ThusVnew=Vold⇒RR2+1ω2C′2=2RR2+1ω2C2⇒K=41−3R2C2ω2−1Thus, m=4, n=3⇒m+n=7