Q.

A parallel-plate capacitor is to be designed, using a  dielectric of dielectric constant 5, so as to have a dielectric strength of 109Vm-1. If the voltage rating of the capacitor is 12 kV, the minimum area of each  plate required to have a capacitance of 80 pF is :

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answer is 1.

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Detailed Solution

d=VE=12  ×  103109 =  12  ×  10−6 mC=kε0Ad   ⇒   A=Cdkε0  =  80  ×  10−12 ×  12  × 10−6  5 ×  8.8  ×  10−12=21.8  ×  10−6  m2
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A parallel-plate capacitor is to be designed, using a  dielectric of dielectric constant 5, so as to have a dielectric strength of 109Vm-1. If the voltage rating of the capacitor is 12 kV, the minimum area of each  plate required to have a capacitance of 80 pF is :