First slide

Magnetic properties of materials

Question

A paramagnetic sample shows a net magnetization of 6 A/m when it is placed in an external magnetic field of 0.4 T at a temperature of 4 K. When the sample is placed in an external magnetic field of 0.3 T at a temperature of 24 K, then the magnetization will be:

Moderate

A

0.75 A/m
B

2.25 A/m
C

1 A/m
D

4 A/m

Solution

$\begin{array}{l} Curie's law : x_{m} α \frac{1}{T} \\ \Rightarrow \frac{I}{H} α \frac{1}{T} \\ \Rightarrow \frac{I_{1} T_{1}}{H_{1}} = \frac{I_{2} T_{2}}{H_{2}} \\ \Rightarrow \frac{6 \times 4}{0.4} = \frac{I_{2} \times 24}{0.3} \\ \Rightarrow I_{2} = 0.75 \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App