A paramagnetic sample shows a net magnetization of 6 A/m when it is placed in an external magnetic field of 0.4 T at a temperature of 4 K. When the sample is placed in an external magnetic field of 0.3 T at a temperature of 24 K, then the magnetization will be:

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0.75 A/m

2.25 A/m

1 A/m

4 A/m

answer is A.

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Detailed Solution

Curie's law :xmα1 T⇒IHα1 T⇒I1 T1H1=I2 T2H2 ⇒6×40.4=I2×240.3⇒I2=0.75

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