A paramagnetic sample shows a net magnetization of 0.8 A/m, when placed in an external magnetic field of strength 0.8 T at a temperature 5 K. When the same sample is placed in an external magnetic field of 0.4 T at a temperature of 20 K, the magnetization is

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0.8 Am–1

0.8 Am–2

0.1 Am

0.1 Am–1

answer is D.

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Detailed Solution

Χ=CT, Χ=IH ; IH=CT 0.80.8=C5I0.4=C20, I=0.1 A/m

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