A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of $20\times {10}^{-3}\text{\hspace{0.17em}J}/\text{T}$, when a magnetic intensity of  $6\times {10}^{3}A/m$ is applied. Its magnetic susceptibility is

Given
Side of cube $=1{\text{\hspace{0.17em}cm=10}}^{-2}\text{\hspace{0.17em}m}$
Magnetic dipole moment  $M=20\times {10}^{-3}\text{\hspace{0.17em}J}/\text{T}$
Magnetic intensity  $H=6\times {10}^3\text{\hspace{0.17em}J}/\text{T}$
Magnetic susceptibility   $\chi =\frac{\text{Intensity of magnetization}}{\text{Magnetic\hspace{0.17em}field\hspace{0.17em}intensity}}$
$\Rightarrow \chi =\frac{I}{H}=\frac{M}{V\times H}=\frac{20\times {10}^{-3}}{{10}^{-6}\times 6\times {10}^3}=\frac{20}{6}=3.33$