Q.
A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20×10−3 J/T, when a magnetic intensity of 6×103 A/m is applied. Its magnetic susceptibility is
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answer is 0003.33.
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Detailed Solution
GivenSide of cube =1 cm=10−2 mMagnetic dipole moment M=20×10−3 J/TMagnetic intensity H=6×103 J/TMagnetic susceptibility χ=Intensity of magnetizationMagnetic field intensity⇒χ=IH=MV×H=20×10−310−6×6×103=206=3.33
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