A paramagnetic substance of susceptibility 3×10−4 is placed in a magnetic field intensity of 6×10−4A.m−1 . Then the intensity of magnetization in the units of A−m−1 is__
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a
1.33×1 0−8
b
0.75×1 0−8
c
18×1 0−8
d
14×1 0−8
answer is C.
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Detailed Solution
Intensity of magnetization is I=χ.Hχ =susceptibility H= magnetic field intensity⇒I=3×10−4×6×10−4 ⇒I=18×10−8Am-1