A paramagnetic substance of susceptibility 3×10−4 is placed in a magnetic field intensity of 6×10−4A.m−1 . Then the intensity of magnetization in the units of A−m−1 is__

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1.33×1 0−8

0.75×1 0−8

18×1 0−8

14×1 0−8

answer is C.

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Detailed Solution

Intensity of magnetization is I=χ.Hχ =susceptibility H= magnetic field intensity⇒I=3×10−4×6×10−4 ⇒I=18×10−8Am-1

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