A paramagnetic substance of susceptibility 2×10−4 is placed in a magnetic intensity of 4×10-4A-m-1. Then the intensity of magnetization in the unit of A-m-1 is
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a
1×10−8A-m-1
b
2×10−4A-m-1
c
8×10−8A-m-1
d
16×10−8A-m-1
answer is C.
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Detailed Solution
Intensity of magnetization is I=χ.H χ =magnetic susceptibility ;H=Magnetic Intensity⇒I=2×10−4×4×10−4 ⇒I=8×10−8 A−m−1