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A parent radioactive nucleus A (decay constant DA) converts into a radioactive nucleus B of decay constant DB. Initially number of atoms of B is zero. At any time NA, NB are number of atoms of nuclei A and B respectively. Then maximum value of NB is

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a

DANADB

b

DBNADA

c

DA+DBNADB

d

DB(DA+DB)NA

answer is A.

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Detailed Solution

[Concept]: NB reaches maximum when activity of A and B will be sameActivity=R=λN where λ is decay constant If R is same then λ1N1=λ2N2[Step 1]: i.e. DANA=DBNB[Step 2]: ∴NB=DANADB

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