A particle is acted upon by a force F which varies with position x as shown in figure. If the particle at x = 0 has kinetic energy of 25 J, then the kinetic energy of the particle at x = 16 m is

Work done W = Area under F-x graph with proper signW = Area of triangle ABC + Area of rectan gle CDEF + Area of rectangle FGHI + Area of rectangle IJKLW = [12×6×10]+[4×(-5)]+[4×(5)]+[2×(-5)]    = 30-20+20-10     = 20JAccording to work energy theoremKf-Ki = Wor (Kf)x=16m-(Ki)x=0m = W     (Kf)x=16m = (Ki)x=0m+W= 25 J+20 J              (Using (i))= 45 J