Questions
A particle can move along x-axis under the influence of a conservative force and variation of its potential energy is as shown in the figure. Then
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a
force acting on the particle is zero at x=x1 and x3
b
force acting on the particle at x=x1, points in the right.
c
force acting on the particle at x=x3, points in the right
d
force acting on the particle at x=x2, points in the left.
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Correct option is B
F=−dUdx=negative of the slope of tangent. Now dUdx is negative at x=x1, so F is positive i.e directed to the right. dUdx is positive at x=x3, dUdx=0, so the force is zero.Similar Questions
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