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Rectilinear Motion

Question

 A particle can move only along x-axis. Three pairs of initial and final positions of particle at two successive times are given 

Pair                   Initial position                    Final position 

 1                             -3m                                  +5m 

 2                             -3m                                   -7m 

 3                             +7m                                 -3m

Find the sum of magnitudes of displacement in the pairs which give negative displacement in m.

Easy
Solution

s1=5(3)=8ms2=7(3)=4ms3=37=10m Required value =s2+s3=(14)=14



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x-coordinate of a particle moving along this  axis is x=2+t2+2t3. Here, x is in meters and t in seconds. Find the position from where it started its journey.


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