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Q.

A particle carrying a charge equal to 100 times the charge on an electron is making one revolution per second in a circular path of radius 0.8 m. The value of the magnetic field produced at the centre will be (μ0 = permeability for vacuum)

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a

10−7μ0

b

10−17 μ0

c

10−6 μ0

d

10−7 μ0

answer is B.

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Detailed Solution

i=qt  =  100 ×  eBcentre  =  μ04π . 2πir  =  μ04π = 2π × 100er= μ0 ×  200 × 1.6 × 10−194 × 0.8 = 10−17  μ0
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