A particle carrying a charge equal to 100 times the charge on an electron, is rotating per sec in a circular path of radius 0.8 m. The value of the magnetic field produced at the centre will be :
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a
10-7/μ0
b
10-17μ0
c
10-6μ0
d
10-7μ0
answer is B.
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Detailed Solution
current due to the charge= 1.6×10-17Athus magnetic field at the center = μo(1.6×10-17)2×0.8 = μ010-17
A particle carrying a charge equal to 100 times the charge on an electron, is rotating per sec in a circular path of radius 0.8 m. The value of the magnetic field produced at the centre will be :