Questions

A particle carrying a charge equal to 100 times the charge on an electron, is rotating per sec in a circular path of radius 0.8 m. The value of the magnetic field produced at the centre will be :

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10-7/μ0

10-17μ0

10-6μ0

10-7μ0

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detailed solution

Correct option is B

current due to the charge= 1.6×10-17Athus magnetic field at the center = μo(1.6×10-17)2×0.8 = μ010-17

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