First slide
Force on a charged particle moving in a magnetic field
Question

A particle of charge per unit mass α is released from origin with velocity v=v0i^ in a magnetic field

B=B0k^  for  x      32   v0B0αand  B=0   for   x  >  32   v0B0α

The x-coordinates of the particle at time t>  π3B0α would be

Difficult
Solution

r=mv0B0q  =  v0B0αxr  =  32  =  sinθ        θ=  600

tQA=T6  =    π3B0α

Therefore x-coordinate of particle at any time t>  π3B0α  will be

x=32   v0B0α  +v0  t  π3B0α  cos600=32v0B0α  +  v02  tπ3B0α

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