A particle of charge per unit mass α is released from origin with velocity v→$$=v$$→$$0i^$$ in a magnetic fieldB→$$=$$−$$B0k^$$ for x ≤ $$32$$ $$v0B0$$αand B→$$=$$ $$0$$ for x $$32$$ $$v0B0$$αThe $$x-coordinates$$ of the particle at time t π$$3B0$$α would be

Question

A particle of charge per unit mass α is released from origin with velocity v→$$=v$$→$$0i^$$ in a magnetic fieldB→$$=$$−$$B0k^$$  for  x   ≤   $$32$$   $$v0B0$$αand  B→$$=$$ $$0$$   for   x  >  $$32$$   $$v0B0$$αThe $$x-coordinates$$ of the particle at time t >  π$$3B0$$α would be

Infinity Learn · Accepted Answer

$$r=mv0B0q$$  $$=$$  $$v0B0$$αxr  $$=$$  $$32$$  $$=$$  $$sin$$ θ   ∴     θ $$=$$  $$600tQA=T6$$  $$=$$    π$$3B0$$αTherefore $$x-coordinate$$ of particle at any time t>  π$$3B0$$α  will $$bex=$$ $$32$$   $$v0B0$$α  $$+$$ $$v0$$  t−  π$$3B0$$α  $$cos600=32v0B0$$α  $$+$$  $$v02$$  t−π$$3B0$$α

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A particle of charge per unit mass α is released from origin with velocity v→=v→0i^ in a magnetic fieldB→=−B0k^ for x ≤ 32 v0B0αand B→= 0 for x > 32 v0B0αThe x-coordinates of the particle at time t > π3B0α would be

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