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Q.

A particle of charge per unit mass α is released from origin with a velocity v→ = v0i^ in a uniform magnetic field B→=−B0k^.  If the particle passes through (0, y, 0), then y is equal to

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a

−2v0B0α

b

v0B0α

c

2v0B0α

d

−v0B0α

answer is C.

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Detailed Solution

y=2r=2mv0B0q= 2v0B0αHere,  qm=α
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