A particle of charge ‘q’ and mass ‘m’ is moving with a velocity −vi^ v≠0 towards a large screen placed in Y-Z plane at a distance d. If there is a magnetic field B→=B0k^, the minimum value of ‘v’ for which the particle will not hit the screen is :

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

qdB02m

2qdB0m

qdB03m

qdB0m

answer is D.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

To avoid the hit, radius of circular motion should be just greater than distance d. ⇒r≥d ⇒mvqB0≥d ⇒νmin=qB0dm

Watch 3-min video & get full concept clarity