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A particle of charge ‘q’ and mass ‘m’ is moving with a velocity $- v \hat{i} (v \neq 0)$ towards a large screen placed in Y-Z plane at a distance d. If there is a magnetic field $\vec{B} = B_{0} \hat{k},$ the minimum value of ‘v’ for which the particle will not hit the screen is :

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detailed solution

Correct option is D

To avoid the hit, radius of circular motion should be just greater than distance d. ⇒r≥d ⇒mvqB0≥d ⇒νmin=qB0dm

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