A particle of charge q and mass m is projected from a large distance towards another identical charged particle at rest with velocity v0. The distance of closest approach will be (Assume negligible gravitational attraction)
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a
q22πε0mv02
b
q2πε0mv02
c
2q2πε0mv02
d
q24πε0mv02
answer is B.
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Detailed Solution
B, Applying conservation of momentum : 2mv = mv0 . .. (i)conservation of energy : 2×12mv2+14πε0q2d=12mv02 ....(ii)(I)⇒ V=v0/2,putting in (2), we get,d=q2πε0mv02