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Q.

A particle of charge q and mass m is projected from a large distance towards another identical charged particle at rest with velocity v0. The distance of closest approach will be (Assume negligible gravitational attraction)

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a

q22πε0mv02

b

q2πε0mv02

c

2q2πε0mv02

d

q24πε0mv02

answer is B.

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Detailed Solution

B, Applying conservation of momentum : 2mv = mv0 . .. (i)conservation of energy : 2×12mv2+14πε0q2d=12mv02               ....(ii)(I)⇒ V=v0/2,putting in (2), we get,d=q2πε0mv02
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