A particle of charge q and mass m starts moving from the origin under the action of an electric field E→=E0i^ and magnetic field B→=B0i^ with a velocity v→=v0j^. The speed of the particle will become 2v0 after a time.
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a
t=2mv0qE0
b
t=2Bqmv0
c
t=3Bqmv0
d
t=3mv0qE0
answer is D.
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Detailed Solution
1. Magnetic field can’t change speed of charged particle, it will only change the direction of velocity v0j^ such that it always lie in y-z plane.2. Since the electric field is in x-direction, hence it would not affect the velocity in the y-z plane. After time t, the electric field will inject some velocityvx in the x- direction such that the magnitude of velocity changes to 2v0. ∴v02+vx2=2v0⇒vx2=4v02−v02=3v02⇒vx=3v03. Electric force F=qE04. Acceleration =Fm5. The time taken by x-component velocity to become from zero to 3v0 due to uniform electric field =vxfinal−vxinitialacceleration=3v0−0a here a=E0qmt=3v0E0qm=3v0mE0qTherefore, the correct answer is D