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Q.

A particle of charge q and mass m is subjected to an electric field E=E01−ax2  in the x-direction, where a and  E0 are constants. Initially the particle was at rest at x = 0. Other than the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is:

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a

1a

b

3a

c

2a

d

a

answer is B.

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Detailed Solution

From work-energy theoremdK=dW=qEdx=qE01-ax2dx∴ΔK=qE0∫0x1-ax2dx =qE0x-ax33=0 ⇒x1-a3x2=0⇒x=0,±3a
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