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Questions  

A particle collides with 15 ms1 at an angle 600 from vertical on a smooth horizontal surface. The coefficient of restitution (e) is 13.   The range R, as shown in diagram will be

a
12.5 m
b
12 m
c
11.25 m
d
12.75 m

detailed solution

Correct option is C

Given e=13tan⁡ϕ=1etan⁡θtan⁡ϕ=3⇒sin⁡ϕ=310Along horizontal,m×15sin⁡60∘=m×vsin⁡ϕv=155102×3=13.7ms−1x=v2sin⁡2π2−ϕg=v2sin⁡2ϕg=(13.7)2×2×31010=11.25m

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