First slide
Work
Question

A  particle is displaced from (1m,1m,1m) to (2m,2m,2m)  under a force  F=(2xyi^+x2j^)N. The work done by this force is

Moderate
Solution

W=Fxdx+Fydy+F2dzW=(1,1,1)(2,2,2)2xi^+x2j^(dxi^+dyj^+dzk^)W=(1,1,1)(2,2,2)2xydx+x2dy=(1,1,1)(2,2,2)dx2yW=x2y(1,1,1)(2,2,2)=81=7J

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App