A particle is displaced from (1m,1m,1m) to (2m,2m,2m) under a force F→=(2xyi^+x2j^)N The work done by this force is
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a
8J
b
7J
c
16J
d
10J
answer is B.
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Detailed Solution
Work done=∫F→.dr → here F=force=iFx+jFy+kFz; dr=displacement=idx+jdy+kdz W = ∫(Fxdx+Fydy+F2dz) W=∫(1,1,1)(2,2,2)(2xyi^+x2j^).(dxi^+dyj^+dzk^) W= ∫(1,1,1)(2,2,2)2xy dx +x2 dy W=22 x2y(1,1,1)(2,2,2)=[22.2-12.1] Work done=8−1=7J