Questions
A particle is displaced from (1m,1m,1m) to (2m,2m,2m) under a force The work done by this force is
detailed solution
Correct option is B
Work done=∫F→.dr → here F=force=iFx+jFy+kFz; dr=displacement=idx+jdy+kdz W = ∫(Fxdx+Fydy+F2dz) W=∫(1,1,1)(2,2,2)(2xyi^+x2j^).(dxi^+dyj^+dzk^) W= ∫(1,1,1)(2,2,2)2xy dx +x2 dy W=22 x2y(1,1,1)(2,2,2)=[22.2-12.1] Work done=8−1=7JSimilar Questions
A force (where K is a positive constant) acts on a particle moving in the xy-plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force F on the particles is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests