Questions
A particle is displaced from a position vector to by applying a force of .The work done is
detailed solution
Correct option is A
Work done=∫F→.dr → here F=force=iFx+jFy+kFz; dr=displacement=idx+jdy+kdz W=∫Fx dx+∫Fy dy +∫Fz dz W=∫423x2 dx+∫202y dy +0 W=3x3342 + 2y2220 W=33[23-43]+22[02-22] W=(8−64)+(0−4)=−56−4 Work done=−60JTalk to our academic expert!
Similar Questions
A force (where K is a positive constant) acts on a particle moving in the xy-plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force F on the particles is
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