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Q.

A particle is displaced from a position vector 4i^+2j^m to 2i^+3k^m by applying a force of f→=3x2i^+2yj^N. The work done is

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a

-60J

b

60J

c

-120J

d

90J

answer is A.

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Detailed Solution

W=∫Fxdx+∫Fydy+∫FzdzW=∫42 3x2dx+∫20 2ydy+0W=3x3342+2y2220W=(8−64)+(0−4)=−56−4W=−60J

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