A particle at the end of a spring executes simple harmonic motion with a period t₁, while the corresponding period for another spring is t₁ If the
period of oscillation with the two springs in series is T , then

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Infinity Learn · Accepted Answer

Here, $$t1=2$$Ï$$mk1$$  or  $$t12=4$$Ï$$2mk1$$  and $$t2=2$$Ï$$mk2$$  or  $$t22=4$$Ï$$2mk2$$ â´ $$t12+t22=4$$Ï$$2m1k1+1k3$$ When the springs are connected h $$seri6s$$, then $$1k=1k1+1k2$$  Now $$T=2$$Ïmk $$=2$$Ï$$m1k1+1k2$$ or $$T2=4$$Ï$$2m1k1+1k2$$ $$T2=4$$Ï$$2m1k1+1k2$$ Fmm eqs. [$$1)$$ atrd (2), we ge $$T2=t12+t22$$

A particle at the end of a spring executes simple harmonic motion with a period t₁, while the corresponding period for another spring is t₁ If the
period of oscillation with the two springs in series is T , then

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A particle at the end of a spring executes simple harmonic motion with a period t1, while the corresponding period for another spring is t1 If theperiod of oscillation with the two springs in series is T , then

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A particle at the end of a spring executes simple harmonic motion with a period t₁, while the corresponding period for another spring is t₁ If the
period of oscillation with the two springs in series is T , then