A particle execute SHM from the mean position. Its amplitude is A, its time period is ‘T’. At what displacement, its speed is half of its maximum speed.
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a
3A2
b
23A
c
2A3
d
3A2
answer is A.
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Detailed Solution
given oscillator speed is V=12Vmax =12Aω.........(1) where maximum velocity Vmax=Aω oscillator velocity is V=ωA2-Y2---(2) substitute (1) in (2) 12Aω=ωA2-Y2 ⇒ 12A=A2-Y2 ⇒14A2=A2-Y2 ⇒ Y2=A2−A24 ⇒ Y2=3A24 ⇒Y=3A2