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Questions  

A particle  execute SHM from the mean position. Its amplitude is A, its time period is ‘T’. At what displacement, its speed is half of its maximum speed.

a
3A2
b
23A
c
2A3
d
3A2

detailed solution

Correct option is A

given oscillator speed is V=12Vmax                                                =12Aω.........(1)   where maximum velocity Vmax=Aω oscillator velocity is V=ωA2-Y2---(2) substitute (1) in (2)  12Aω=ωA2-Y2 ⇒ 12A=A2-Y2  ⇒14A2=A2-Y2 ⇒ Y2=A2−A24  ⇒ Y2=3A24 ⇒Y=3A2

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Similar Questions

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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