Questions
A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
detailed solution
Correct option is C
Velocity v=ωA2−x2 and acceleration =ω2xNow given, ω2x=ωA2−x2 ⇒ω2.1=ω22−12 ⇒ω=3 ∴T=2πω=2π3Talk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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