Questions
A particle executes SHM on a straight line path. The amplitude of oscillation is 2 cm. When the displacement of the particle from the mean position is I cm, the numerical value of magnitude of acceleration is equal to the numerical value of magnitude of velocity. Then find out the frequency of SHM.
detailed solution
Correct option is A
The speed of particle at a distance x = I from mean position isv = ωA2-x2 = ω22-12 = 3 s ...(i)The magnitude of acceleration at x = I isa = ω2x = ω2--------(ii)from equation (i) and (ii)ω2 = 3ω ⇒ω = 3or f = ω2π= 32πTalk to our academic expert!
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The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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