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Q.

A particle executes SHM on a straight line path. The amplitude of oscillation is 2 cm. When the displacement of the particle from the mean position is I cm, the numerical value of magnitude of acceleration is equal to the numerical value of magnitude of velocity. Then find out the frequency of SHM.

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a

32π

b

32π

c

32 π

d

3π

answer is A.

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Detailed Solution

The speed of particle at a distance x = I from mean position isv = ωA2-x2 = ω22-12 = 3 s ...(i)The magnitude of acceleration at x = I isa = ω2x = ω2--------(ii)from equation (i) and (ii)ω2 = 3ω ⇒ω = 3or f = ω2π= 32π

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