A particle executes SHM of time period T. The time taken by the particle to move from mean position to the position where its kinetic energy is equal to potential energy is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
T3
b
T4
c
T6
d
T8
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
x=Asinωtv=ωA2−x2 So, KE=12mv2=12mω2A2−12mω2x2 And PE=12Kx2=12mω2x2PE=KE⇒12mω2A2−12mω2x2=12mω2x2⇒x=±A2 Let us consider motion from x=0 to x=A2A2=Asinωtωt=π4,3π4,9π4,11π4,…⇒t=T8,3T8,9T8,11T8,..