First slide

Simple harmonic motion

Question

A particle executes S.H.M. with a period of 6 second and amplitude of 3 cm. Its maximum speed in cm/sec is

Easy

A

$π / 2$
B

$π$
C

$2 π$
D

$3 π$

Solution

$v_{\max} = aω = a \frac{2 π}{T} = 3 \times \frac{2 π}{6} = π cm / s$

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