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Q.

A particle executes SHM with a time period of 16 s. At time t = 2s, the particle crosses the mean position while at t = 4s, its velocity is 4ms–1. The amplitude of motion in metre is

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a

b

162π

c

322/π

d

4/π

answer is C.

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Detailed Solution

y1=Asin2πT×t;V=ωA2-y12
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