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Q.

A particle executes simple harmonic motion along a straight line with an amplitude A. The potential energy is maximum when the displacement is

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a

±A

b

Zero

c

±A2

d

±A2

answer is A.

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Detailed Solution

P.E. =12mω2x2It is clear P.E. will be maximum when x will be maximum i.e., at  x=±A
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