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A particle executes simple harmonic motion along a straight line with maximum velocity 4 m/s and maximum acceleration 2π m/s2. If the particle starts its motion from mean position, then the minimum time after which its speed will be 2 m/s is

a
32 sec
b
23 sec
c
1/2 sec
d
1 sec

detailed solution

Correct option is B

ω=2πT=ω2AωA=amaxVmax=2π4⇒T=4secNow V=Vm.cosωt⇒cos2πTt=24⇒2πtT=π3⇒t=46s=23S

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