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Questions  

A particle executes simple harmonic motion (amplitude = A) between x=A  and x=+A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then 

a
T1
b
T1>T2
c
T1=T2
d
T1=2T2

detailed solution

Correct option is A

Using  x=AsinωtFor  x=A/2,  sinωT1=1/2⇒T1=π6ωFor  x=A,​ sinω(T1+T2)=1⇒T1+T2=π2ω⇒T2=π2ω−T1=π2ω−π6ω=π3ωi.e.​ T1

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