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Questions  

A particle executes simple harmonic motion (amplitude = A) between .x = -A and x = +A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then

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a
T1
b
T1>T2
c
T1=T2
d
T1=2T2

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detailed solution

Correct option is A

Using x=Asin⁡ωt For  x=A/2,sin⁡ωT1=1/2⇒T1=π6ω For  x=A,sin⁡ωT1+T2=1⇒T1+T2=π2ω⇒T2=π2ω−T1=π2ω−π6ω=π3ωi.e.T1


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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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