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A particle executes simple harmonic motion and is located at  x=a,b and  c at times to,3to and 5to respectively with respect to mean position . At  t=0, the particle is at the mean position and moving toward positive x-axis. The frequency of the oscillation is 

a
12πtocos−1a+b2c
b
12πtocos−1a+b3c
c
14πtocos−1a+c2b
d
12πtocos−1a+c2b

detailed solution

Correct option is C

Using y=Asin⁡ωta=Asin⁡ωt0b=Asin⁡3ωt0c=Asin⁡5ωt0a+c=Asin⁡ωt0+Asin⁡5ωt0=2Asin⁡3ωt0cos⁡2ωt0=2bcos⁡2ωt0⇒a+cb=2cos⁡2ωt0⇒a+c2b=cos⁡2ωt0⇒ω=12t0cos−1⁡a+c2b(∵ω=2πf)⇒f=14πt0×cos−1⁡a+c2bTherefore, the correct answer is (C).

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