First slide

Simple harmonic motion

Question

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude

Moderate

A

T / 2
B

T / 4
C

T / 8
D

T / 12

Solution

$y = Asinωt$ $= Asin (\frac{2 π}{T} t)$ $\Rightarrow \frac{A}{2} = Asin \frac{2 πt}{T}$ $\Rightarrow t = \frac{T}{12}$

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