Questions
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then its periodic time (in seconds) is
detailed solution
Correct option is B
At this time (when x=4 cm) velocity and acceleration have same magnitudeGiven A=5 cm and at displacement x=4cm, velocity = acceleration ⇒ωA2-x2=−ω2x ⇒52-42=ω(4) ⇒ω=34=2πT ⇒T=8π3Talk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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